trigonometry

Question: If $\cos 3x+\sin \left( 2x-\frac{7\pi }{6} \right)=-2$, then $x=$ (where $k\in Z$)



1) $\frac{\pi }{3}(6k+1)$
2) $\frac{\pi }{3}(6k+1)$
3) $\frac{\pi }{3}(2k+1)$
4) None of these
Solution: Explanation: No Explanation
Solution of trigonometric equations

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