trigonometry

Question: If $\tan \theta -\sqrt{2}\sec \theta =\sqrt{3}$, then the general value of $\theta $ is



1) $n\pi +{{(-1)}^{n}}\frac{\pi }{4}-\frac{\pi }{3}$
2) $n\pi +{{(-1)}^{n}}\frac{\pi }{3}-\frac{\pi }{4}$
3) $n\pi +{{(-1)}^{n}}\frac{\pi }{3}+\frac{\pi }{4}$
4) $n\pi +{{(-1)}^{n}}\frac{\pi }{4}+\frac{\pi }{3}$
Solution: Explanation: No Explanation
Solution of trigonometric equations

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