trigonometry

Question: If ${{\tan }^{2}}\theta -(1+\sqrt{3})\tan \theta +\sqrt{3}=0$, then the general value of $\theta $ is



1) $n\pi +\frac{\pi }{4},n\pi +\frac{\pi }{3}$
2) $n\pi -\frac{\pi }{4},n\pi +\frac{\pi }{3}$
3) $n\pi +\frac{\pi }{4},n\pi -\frac{\pi }{3}$
4) $n\pi -\frac{\pi }{4},n\pi -\frac{\pi }{3}$
Solution: Explanation: No Explanation
Solution of trigonometric equations

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