trigonometry

Question: If $\frac{1-{{\tan }^{2}}\theta }{{{\sec }^{2}}\theta }=\frac{1}{2}$, then the general value of $\theta $is



1) $n\pi \pm \frac{\pi }{6}$
2) $n\pi +\frac{\pi }{6}$
3) $2n\pi \pm \frac{\pi }{6}$
4) None of these
Solution: Explanation: No Explanation
Solution of trigonometric equations

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