trigonometry

Question: If $\sqrt{3}\tan 2\theta +\sqrt{3}\tan 3\theta +\tan 2\theta \tan 3\theta =1$, then the general value of$\theta $ is

1) $n\pi +\frac{\pi }{5}$

2) $\left( n+\frac{1}{6} \right)\frac{\pi }{5}$

3) $\left( 2n\pm \frac{1}{6} \right)\frac{\pi }{5}$

4) $\left( n+\frac{1}{3} \right)\frac{\pi }{5}$

Solution:

Explanation: No Explanation

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