trigonometry

Question: Let$0<x<\frac{\pi }{4}.$Then $\sec 2x-\tan 2x=$



1) $\tan \left( x-\frac{\pi }{4} \right)$
2) $\tan \left( \frac{\pi }{4}-x \right)$
3) $\tan \left( x+\frac{\pi }{4} \right)$
4) ${{\tan }^{2}}\left( x+\frac{\pi }{4} \right)$
Solution: Explanation: No Solution
Trigonometric ratios of multiple and sub-multiple angles

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