trigonometry

Question: If $\sin \alpha =\frac{-3}{5},$where $\pi <\alpha <\frac{3\pi }{2},$then $\cos \frac{1}{2}\alpha =$



1) $\frac{-1}{\sqrt{10}}$
2) $\frac{1}{\sqrt{10}}$
3) $\frac{3}{\sqrt{10}}$
4) $\frac{-3}{\sqrt{10}}$
Solution: Explanation: No Solution
Trigonometric ratios of multiple and sub-multiple angles

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