trigonometry

Question: If $\tan \beta =\cos \theta \tan \alpha ,$then ${{\tan }^{2}}\frac{\theta }{2}=$



1) $\frac{\sin (\alpha +\beta )}{\sin (\alpha -\beta )}$
2) $\frac{\cos (\alpha -\beta )}{\cos (\alpha +\beta )}$
3) $\frac{\sin (\alpha -\beta )}{\sin (\alpha +\beta )}$
4) $\frac{\cos (\alpha +\beta )}{\cos (\alpha -\beta )}$
Solution: Explanation: No Solution
Trigonometric ratios of multiple and sub-multiple angles

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