trigonometry

Question: $\frac{\sin 3\theta +\sin 5\theta +\sin 7\theta +\sin 9\theta }{\cos 3\theta +\cos 5\theta +\cos 7\theta +\cos 9\theta }=$



1) $\tan 3\theta $
2) $\cot 3\theta $
3) $\tan 6\theta $
4) $\cot 6\theta $
Solution: Explanation: No Solution
Trigonometric ratios of sum and difference of two and three

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