trigonometry

Question: If $\tan \alpha ,\tan \beta $are the roots of the equation ${{x}^{2}}+px+q=0\text{ }(p\ne 0),$ then

1) ${{\sin }^{2}}(\alpha +\beta )+p\sin (\alpha +\beta )\cos (\alpha +\beta )+q{{\cos }^{2}}(\alpha +\beta )=q$

2) $\tan (\alpha +\beta )=\frac{p}{q-1}$

3) $\cos (\alpha +\beta )=1-q$

4) $\sin (\alpha +\beta )=-p$

Solution:

Explanation: No Solution

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)