trigonometry

Question: ${{\cos }^{2}}48{}^\circ -{{\sin }^{2}}12{}^\circ =$



1) $\frac{\sqrt{5}-1}{4}$
2) $\frac{\sqrt{5}+1}{8}$
3) $\frac{\sqrt{3}-1}{4}$
4) $\frac{\sqrt{3}+1}{2\sqrt{2}}$
Solution: Explanation: No Solution
Trigonometric ratios of sum and difference of two and three

Rate this question:

Average rating: (0 votes)

Previous Question Next Question