trigonometry

Question: Given that $\pi <\alpha <\frac{3\pi }{2},$ then the expression $\sqrt{(4{{\sin }^{4}}\alpha +{{\sin }^{2}}2\alpha )}+4{{\cos }^{2}}\left( \frac{\pi }{4}-\frac{\alpha }{2} \right)$ is equal to



1) 2
2) $2+4\sin \alpha $
3) $2-4\sin \alpha $
4) None of these
Solution: Explanation: No Solution
Fundamental trigonometrical ratios and functions Trigonometrical ratio of allied angles

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