Categories > trigonometry > Fundamental trigonometrical ratios and functions > If $\pi <\alpha <\frac{3\pi }{2}$, then $\sqrt{\frac{1-\cos \alpha }{1+\cos \alpha }}+\sqrt{\frac{1+\cos \alpha }{1-\cos \alpha }}$=

trigonometry

Question: If $\pi <\alpha <\frac{3\pi }{2}$, then $\sqrt{\frac{1-\cos \alpha }{1+\cos \alpha }}+\sqrt{\frac{1+\cos \alpha }{1-\cos \alpha }}$=


1) $\frac{2}{\sin \alpha }$
2) $-\frac{2}{\sin \alpha }$
3) $\frac{1}{\sin \alpha }$
4) $-\frac{1}{\sin \alpha }$
Solution: Explanation: No Solution
Fundamental trigonometrical ratios and functions Trigonometrical ratio of allied angles

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