Categories > trigonometry > Fundamental trigonometrical ratios and functions > The equation ${{\sec }^{2}}\theta =\frac{4xy}{{{(x+y)}^{2}}}$is only possible when

trigonometry

Question: The equation ${{\sec }^{2}}\theta =\frac{4xy}{{{(x+y)}^{2}}}$is only possible when


1) $x=y$
2) $x < y$
3) $x>y$
4) None of these
Solution: Explanation: No Solution
Fundamental trigonometrical ratios and functions Trigonometrical ratio of allied angles

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