A solution containing $N{a_2}C{O_3}$ and $ NaOH $ requires 300 ml of 0.1 N HCl using phenolpthalein as an indicator. Methyl orange is then added to the above titrated solution when a further 25 ml of 0.2 N HCl is required. The amount of NaOH present in solution is $(NaOH = 40,\,N{a_2}C{O_3} = 106)$