chemical-aritmatic

Question: The number of oxygen atoms in 4.4 g of $C{O_2}$is approx.

1) $1.2 \times {10^{23}}$

2) $6 \times {10^{22}}$

3) $6 \times {10^{23}}$

4) $12 \times {10^{23}}$

Solution:

Explanation: No Explanation

mole-concept

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