chemical-aritmatic

Question: On reduction with hydrogen, 3.6 g of an oxide of metal left 3.2 g of metal. If the vapour density of metal is 32, the simplest formula of the oxide would be

1) $MO$

2) ${M_2}{O_3}$

3) ${M_2}O$

4) ${M_2}{O_5}$

Solution:

Explanation: No Explanation

atomic-mass

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