chemical-aritmatic

Question: In the reaction $2N{a_2}{S_2}{O_3} + {I_2} \to N{a_2}{S_4}{O_6} + 2NaI$, the equivalent weight of $N{a_2}{S_2}{O_3}$(mol.wt.= M) is equal to

1) M

2) $M/2$

3) $M/3$

4) $M/4$

Solution:

Explanation: No Explanation

atomic-mass

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)