Categories > waves > Interference > Two sound waves (expressed in CGS units) given by ${{y}_{1}}=0.3\sin \frac{2\pi }{\lambda }(vt-x)$ and ${{y}_{2}}=0.4\sin \frac{2\pi }{\lambda }(vt-x+\theta )$ interfere. The resultant amplitude at a place where phase difference is $\pi /2$ will be

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Question: Two sound waves (expressed in CGS units) given by ${{y}_{1}}=0.3\sin \frac{2\pi }{\lambda }(vt-x)$ and ${{y}_{2}}=0.4\sin \frac{2\pi }{\lambda }(vt-x+\theta )$ interfere. The resultant amplitude at a place where phase difference is $\pi /2$ will be


1) 0.7 cm
2) 0.1 cm
3) 0.5 cm
4) $\frac{1}{10}\sqrt{7}\,cm$
Solution: Explanation: No Explanation
Interference Superposition of Waves

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