Categories > waves > Interference > Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is $a$ and the phase of A is ahead by $\frac{\pi }{3}$ than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter

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Question: Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is $a$ and the phase of A is ahead by $\frac{\pi }{3}$ than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter


1) $2a$
2) $a\sqrt{3}$
3) $a\sqrt{2}$
4) $a$
Solution: Explanation: No Explanation
Interference Superposition of Waves

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