waves

Question: When two sound waves with a phase difference of $\pi /2$, and each having amplitude A and frequency $\omega $, are superimposed on each other, then the maximum amplitude and frequency of resultant wave is

1) $\frac{A}{\sqrt{2}}:\frac{\omega }{2}$

2) $\frac{A}{\sqrt{2}}:\omega $

3) $\sqrt{2}\,A:\frac{\omega }{2}$

4) $\sqrt{2}\,A:\omega $

Solution:

Explanation: No Explanation

Interference Superposition of Waves

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