waves

Question: If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s, then the frequency for the second note is



1) $4\times \frac{330}{4}Hz$
2) $3\times \frac{330}{4}Hz$
3) $2\times \frac{330}{4}Hz$
4) $2\times \frac{4}{330}Hz$
Solution: Explanation: No Explanation
Organ Pipe Vibration of air column

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