Categories > waves > Progressive Waves > The phase difference between two waves represented by ${{y}_{1}}={{10}^{-6}}\sin [100\,t+(x/50)+0.5]m$ and ${{y}_{2}}={{10}^{-6}}\cos \,[100\,t+(x/50)]m$ where $x$ is expressed in metres and $t$ is expressed in seconds, is approximately

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Question: The phase difference between two waves represented by ${{y}_{1}}={{10}^{-6}}\sin [100\,t+(x/50)+0.5]m$ and ${{y}_{2}}={{10}^{-6}}\cos \,[100\,t+(x/50)]m$ where $x$ is expressed in metres and $t$ is expressed in seconds, is approximately


1) 1.5 rad
2) 1.07 rad
3) 2.07 rad
4) 0.5 rad
Solution: Explanation: No Explanation
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