A mass m is suspended separately by two different springs of spring constant $K_1$ and $K_2$ gives the time-period ${{t}_{1}}$ and ${{t}_{2}}$ respectively. If same mass m is connected by both springs as shown in figure then time-period t is given by the relation

Question

Accepted Answer

${{t}^{-2}}={{t}_{1}}^{-2}+{{t}_{2}}^{-2}$

Answer

$t={{t}_{1}}+{{t}_{2}}$

Answer

$t=\frac{{{t}_{1}}.{{t}_{2}}}{{{t}_{1}}+{{t}_{2}}}$

Answer

${{t}^{2}}={{t}_{1}}^{2}+{{t}_{2}}^{2}$

Oscillations

Question: A mass m is suspended separately by two different springs of spring constant $K_1$ and $K_2$ gives the time-period ${{t}_{1}}$ and ${{t}_{2}}$ respectively. If same mass m is connected by both springs as shown in figure then time-period t is given by the relation

Oscillations

Question: A mass m is suspended separately by two different springs of spring constant $K_1$ and $K_2$ gives the time-period ${{t}_{1}}$ and ${{t}_{2}}$ respectively. If same mass m is connected by both springs as shown in figure then time-period t is given by the relation

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