Oscillations

Question: The period of a simple pendulum measured inside a stationary lift is found to be $T$. If the lift starts accelerating upwards with acceleration of $g/3,$then the time period of the pendulum is



1) $\frac{T}{\sqrt{3}}$
2) $\frac{T}{3}$
3) $\frac{\sqrt{3}}{2}T$
4) $\sqrt{3}\,T$
Solution: Explanation: No Explanation
Simple Pendulum

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