Oscillations

Question: A pendulum bob has a speed of $3 m/s$ at its lowest position. The pendulum is $0.5 m$ long. The speed of the bob, when the length makes an angle of ${{60}^{o}}$ to the vertical, will be (If $g=10m/{{s}^{2}}$)



1) $\frac{E}{4}$
2) $\frac{3E}{4}$
3) $\frac{\sqrt{3}}{4}E$
4) ${{K}_{1}}$
Solution: Explanation: No Explanation
Simple Pendulum

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