Categories > Oscillations > Simple Pendulum > The bob of a pendulum of length $l$ is pulled aside from its equilibrium position through an angle $\theta $ and then released. The bob will then pass through its equilibrium position with a speed $v$, where v equals

Oscillations

Question: The bob of a pendulum of length $l$ is pulled aside from its equilibrium position through an angle $\theta $ and then released. The bob will then pass through its equilibrium position with a speed $v$, where v equals


1) $U=K{{X}^{2}}$
2) $\sqrt{2gl(1+\cos \theta )}$
3) $U=KX$
4) $\frac{a}{2}$
Solution: Explanation: No Explanation
Simple Pendulum

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