Categories > Oscillations > Simple Pendulum > A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$, then the time period is given by $T=2\pi \sqrt{\frac{l}{{{g}'}}}$, where ${g}'$ is equal to

Oscillations

Question: A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$, then the time period is given by $T=2\pi \sqrt{\frac{l}{{{g}'}}}$, where ${g}'$ is equal to


1) $g$
2) $g-a$
3) $g+a$
4) $\sqrt{{{g}^{2}}+{{a}^{2}}}$
Solution: Explanation: No Explanation
Simple Pendulum

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