Categories > Oscillations > Time Period and Frequency > A particle in SHM is described by the displacement equation $x(t)=A\cos (\omega t + \theta )$. If the initial ($t = 0$) position of the particle is 1 cm and its initial velocity is $\pi $cm/s, what is its amplitude? The angular frequency of the particle is $\pi {{s}^{-1}}$

Oscillations

Question: A particle in SHM is described by the displacement equation $x(t)=A\cos (\omega t + \theta )$. If the initial ($t = 0$) position of the particle is 1 cm and its initial velocity is $\pi $cm/s, what is its amplitude? The angular frequency of the particle is $\pi {{s}^{-1}}$


1) 1 cm
2) $\sqrt{2}$cm
3) 2 cm
4) 2.5 cm
Solution: Explanation: No Explanation
Time Period and Frequency

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)

Previous Question Next Question

Related Questions