The angular velocity and the amplitude of a simple pendulum is $\omega $ and $a$ respectively. At a displacement $X$ from the mean position if its kinetic energy is $T$ and potential energy is $V$, then the ratio of $T$ to $V$ is

Question

Accepted Answer

$({{a}^{2}}-{{X}^{2}})/{{X}^{2}}$

Answer

${{X}^{2}}{{\omega }^{2}}/({{a}^{2}}-{{X}^{2}}{{\omega }^{2}})$

Answer

${{X}^{2}}/({{a}^{2}}-{{X}^{2}})$

Answer

$({{a}^{2}}-{{X}^{2}}{{\omega }^{2}})/{{X}^{2}}{{\omega }^{2}}$

Oscillations

Question: The angular velocity and the amplitude of a simple pendulum is $\omega $ and $a$ respectively. At a displacement $X$ from the mean position if its kinetic energy is $T$ and potential energy is $V$, then the ratio of $T$ to $V$ is

Oscillations

Question: The angular velocity and the amplitude of a simple pendulum is $\omega $ and $a$ respectively. At a displacement $X$ from the mean position if its kinetic energy is $T$ and potential energy is $V$, then the ratio of $T$ to $V$ is

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