Categories > Oscillations > Acceleration of SHM > A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

Oscillations

Question: A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is


1) $\frac{1}{2\pi \sqrt{3}}$
2) $2\pi \sqrt{3}$
3) $\frac{2\pi }{\sqrt{3}}$
4) $\frac{\sqrt{3}}{2\pi }$
Solution: Explanation: No Explanation
Acceleration of SHM

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