Oscillations

Question: A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position the velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is



1) $\sqrt{3}\,cm$
2) $\sqrt{5}\,cm$
3) $2(\sqrt{3})\,cm$
4) $2(\sqrt{5})\,cm$
Solution: Explanation: No Explanation
Velocity of SHM

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