Oscillations

Question: A simple pendulum performs simple harmonic motion about $X = 0$ with an amplitude $A$ and time period $T$. The speed of the pendulum at $X=\frac{A}{2}$ will be

1) $\frac{\pi A\sqrt{3}}{T}$

2) $\frac{\pi A}{T}$

3) $\frac{\pi A\sqrt{3}}{2T}$

4) $\frac{3{{\pi }^{2}}A}{T}$

Solution:

Explanation: No Explanation

Velocity of SHM

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