Oscillations

Question: Two simple harmonic motions are represented by the equations ${{y}_{1}}=0.1\sin \left( 100\pi t+\frac{\pi }{3} \right)$and ${{y}_{2}}=0.1\cos \pi t.$ The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is



1) $\frac{-\pi }{3}$
2) $\frac{\pi }{6}$
3) $\frac{-\pi }{6}$
4) $\frac{\pi }{3}$
Solution: Explanation: No Explanation
Displacement of SHM Phase

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