Categories > Oscillations > Displacement of SHM > A particle in S.H.M. is described by the displacement function $x(t)=a\cos (\omega t+\theta )$. If the initial $(t=0)$ position of the particle is 1 cm and its initial velocity is $\pi \,cm/s$. The angular frequency of the particle is $\pi \,rad/s$, then it’s amplitude is

Oscillations

Question: A particle in S.H.M. is described by the displacement function $x(t)=a\cos (\omega t+\theta )$. If the initial $(t=0)$ position of the particle is 1 cm and its initial velocity is $\pi \,cm/s$. The angular frequency of the particle is $\pi \,rad/s$, then it’s amplitude is


1) 1 cm
2) $\sqrt{2}\,cm$
3) 2 cm
4) 2.5 cm
Solution: Explanation: No Explanation
Displacement of SHM Phase

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