Categories > Kinetic Theory of Gases > rms speed > Let A and B the two gases and given : $\frac{{{T}_{A}}}{{{M}_{A}}}=4.\frac{{{T}_{B}}}{{{M}_{B}}};$ where $T$ is the temperature and M is molecular mass. If ${{C}_{A}}$ and ${{C}_{B}}$ are the r.m.s. speed, then the ratio $\frac{{{C}_{A}}}{{{C}_{B}}}$ will be equal to

Kinetic Theory of Gases

Question: Let A and B the two gases and given : $\frac{{{T}_{A}}}{{{M}_{A}}}=4.\frac{{{T}_{B}}}{{{M}_{B}}};$ where $T$ is the temperature and M is molecular mass. If ${{C}_{A}}$ and ${{C}_{B}}$ are the r.m.s. speed, then the ratio $\frac{{{C}_{A}}}{{{C}_{B}}}$ will be equal to


1) 2
2) 4
3) 1
4) 0.5
Solution: Explanation: No Explanation
rms speed speed of gas

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