thermodynamics

Question: Work done per mol in an isothermal change is

1) $RT{{\log }_{10}}\frac{{{V}_{2}}}{{{V}_{1}}}$

2) $RT{{\log }_{10}}\frac{{{V}_{1}}}{{{V}_{2}}}$

3) $RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}}$

4) $RT{{\log }_{e}}\frac{{{V}_{1}}}{{{V}_{2}}}$

Solution:

Explanation: No Explanation

Isothermal Process

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