thermodynamics

Question: For an isothermal expansion of a perfect gas, the value of $\frac{\Delta P}{P}$ is equal



1) $-{{\gamma }^{1/2}}\frac{\Delta V}{V}$
2) $-\frac{\Delta V}{V}$
3) $-\gamma \frac{\Delta V}{V}$
4) $-{{\gamma }^{2}}\frac{\Delta V}{V}$
Solution: Explanation: No Explanation
Isothermal Process

Rate this question:

Average rating: (0 votes)

Previous Question Next Question