Mechanical Properties of Fluids

Question: The radii of two soap bubbles are $r_1$ and $r_2$. In isothermal conditions, two meet together in vaccum. Then the radius of the resultant bubble is given by

1) $R=({{r}_{1}}+{{r}_{2}})/2$

2) $R={{r}_{1}}({{r}_{1}}{{r}_{2}}+{{r}_{2}})$

3) ${{R}^{2}}=r_{1}^{2}+r_{2}^{2}$

4) $R={{r}_{1}}+{{r}_{2}}$

Solution:

Explanation: No Explanation

Surface Tension Excess Pressure

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