Mechanical Properties of Fluids

Question: A drop of mercury of radius $2$ mm is split into $8$ identical droplets. Find the increase in surface energy. (Surface tension of mercury is $0.465\ J/{{m}^{2}}$)



1) $23.4\mu J$
2) $18.5\mu J$
3) $26.8\mu J$
4) $16.8\mu J$
Solution: Explanation: No Explanation
Surface tension surface energy

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