Mechanical Properties of Fluids

Question: The work done in increasing the size of a soap film from $10 cm \times 6 cm$ to $10 cm \times 11 cm$ is $3 \times 10^{-4}$ joule. The surface tension of the film is



1) $1.5\times {{10}^{-2}}N/m$
2) $3.0\times {{10}^{-2}}N/m$
3) $6.0\times {{10}^{-2}}N/m$
4) $11.0\times {{10}^{-2}}N/m$
Solution: Explanation: No Explanation
Surface tension surface energy

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