What is the velocity v of a metallic ball of radius r falling in a tank of liquid at the instant when its acceleration is one-half that of a freely falling body ? (The densities of metal and of liquid are $\rho$ and $\sigma$ respectively, and the viscosity of the liquid is $\eta$).

Question

Accepted Answer

$\frac{{{r}^{2}}g}{9\eta }(\rho -\sigma )$

Answer

$\frac{{{r}^{2}}g}{9\eta }(\rho -2\sigma )$

Answer

$\frac{{{r}^{2}}g}{9\eta }(2\rho -\sigma )$

Answer

$\frac{2{{r}^{2}}g}{9\eta }(\rho -\sigma )$

Mechanical Properties of Fluids

Question: What is the velocity v of a metallic ball of radius r falling in a tank of liquid at the instant when its acceleration is one-half that of a freely falling body ? (The densities of metal and of liquid are $\rho$ and $\sigma$ respectively, and the viscosity of the liquid is $\eta$).

Mechanical Properties of Fluids

Question: What is the velocity v of a metallic ball of radius r falling in a tank of liquid at the instant when its acceleration is one-half that of a freely falling body ? (The densities of metal and of liquid are $\rho$ and $\sigma$ respectively, and the viscosity of the liquid is $\eta$).

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