Mechanical Properties of Fluids

Question: Two capillary tubes of the same length but different radii $r_1$ and $r_2$ are fitted in parallel to the bottom of a vessel. The pressure head is $P$. What should be the radius of a single tube that can replace the two tubes so that the rate of flow is same as before



1) ${{r}_{1}}+{{r}_{2}}$
2) $r_{1}^{2}+r_{2}^{2}$
3) $r_{1}^{4}+r_{2}^{4}$
4) None of these
Solution: Explanation: No Explanation
Fluid Flow

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