Mechanical Properties of Fluids

Question: A liquid flows in a tube from left to right as shown in figure. ${{A}_{1}}$ and ${{A}_{2}}$ are the cross-sections of the portions of the tube as shown. Then the ratio of speeds ${{v}_{1}}/{{v}_{2}}$ will be

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1) ${{A}_{1}}/{{A}_{2}}$
2) ${{A}_{2}}/{{A}_{1}}$
3) $\sqrt{{{A}_{2}}}/\sqrt{{{A}_{1}}}$
4) $\sqrt{{{A}_{1}}}/\sqrt{{{A}_{2}}}$
Solution: Explanation: No Explanation
Fluid Flow

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