Mechanical Properties of Fluids

Question: A ball of radius $r$ and density $\rho$ falls freely under gravity through a distance $h$ before entering water. Velocity of ball does not change even on entering water. If viscosity of water is $\eta$, the value of $h$ is given by

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1) $\frac{2}{9}{{r}^{2}}\left( \frac{1-\rho }{\eta } \right)\,g$
2) $\frac{2}{81}{{r}^{2}}\left( \frac{\rho -1}{\eta } \right)\,g$
3) $\frac{2}{81}{{r}^{4}}{{\left( \frac{\rho -1}{\eta } \right)}^{2}}g$
4) $\frac{2}{9}{{r}^{4}}{{\left( \frac{\rho -1}{\eta } \right)}^{2}}g$
Solution: Explanation: No Explanation
Fluid Flow

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