Mechanical Properties of Solids

Question: When a 4 kg mass is hung vertically on a light spring that obeys Hooke's law, the spring stretches by 2 cms. The work required to be done by an external agent in stretching this spring by 5 cms will be $(g=9.8\,metres/sec^{2})$



1) 4.900 joule
2) 2.450 joule
3) 0.495 joule
4) 0.245 joule
Solution: Explanation: No Explanation
Work Done in Stretching a Wire

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