The coefficient of linear expansion of brass and steel are ${{\alpha }_{1}}$ and ${{\alpha }_{2}}$. If we take a brass rod of length ${{l}_{1}}$ and steel rod of length ${{l}_{2}}$ at 0°C, their difference in length $({{l}_{2}}-{{l}_{1}})$ will remain the same at a temperature if

Question

Accepted Answer

${{\alpha }_{1}}{{l}_{1}}={{\alpha }_{2}}{{l}_{2}}$

Answer

${{\alpha }_{1}}{{l}_{2}}={{\alpha }_{2}}{{l}_{1}}$

Answer

${{\alpha }_{1}}l_{2}^{2}={{\alpha }_{2}}l_{1}^{2}$

Answer

$\alpha _{1}^{2}{{l}_{1}}=\alpha _{2}^{2}{{l}_{2}}$

Mechanical Properties of Solids

Question: The coefficient of linear expansion of brass and steel are ${{\alpha }_{1}}$ and ${{\alpha }_{2}}$. If we take a brass rod of length ${{l}_{1}}$ and steel rod of length ${{l}_{2}}$ at 0°C, their difference in length $({{l}_{2}}-{{l}_{1}})$ will remain the same at a temperature if

Mechanical Properties of Solids

Question: The coefficient of linear expansion of brass and steel are ${{\alpha }_{1}}$ and ${{\alpha }_{2}}$. If we take a brass rod of length ${{l}_{1}}$ and steel rod of length ${{l}_{2}}$ at 0°C, their difference in length $({{l}_{2}}-{{l}_{1}})$ will remain the same at a temperature if

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