Mechanical Properties of Solids

Question: The length of a wire is $1.0 m$ and the area of cross-section is $1.0\times {{10}^{-2}}\,c{{m}^{2}}$. If the work done for increase in length by $0.2 cm$ is $0.4 joule$, then Young's modulus of the material of the wire is



1) $2.0\times {{10}^{10}}\,N/{{m}^{2}}$
2) $4\times {{10}^{10}}\,N/{{m}^{2}}$
3) $2.0\times {{10}^{11}}\,N/{{m}^{2}}$
4) $2\times {{10}^{10}}\,N/{{m}^{2}}$
Solution: Explanation: No Explanation
Young’s Modulus Breaking Stress

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