Mechanical Properties of Solids

Question: A weight of $200 kg$ is suspended by vertical wire of length $600.5 cm$. The area of cross-section of wire is $1\,m{{m}^{2}}$. When the load is removed, the wire contracts by $0.5 cm$. The Young's modulus of the material of wire will be



1) $2.35\times {{10}^{12}}\,N/{{m}^{2}}$
2) $1.35\times {{10}^{10}}\,N/{{m}^{2}}$
3) $13.5\times {{10}^{11}}\,N/{{m}^{2}}$
4) $23.5\times {{10}^{9}}\,N/{{m}^{2}}$
Solution: Explanation: No Explanation
Young’s Modulus Breaking Stress

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