Mechanical Properties of Solids

Question: In CGS system, the Young's modulus of a steel wire is $2\times {{10}^{12}}$. To double the length of a wire of unit cross-section area, the force required is

1) $4\times {{10}^{6}}$dynes

2) $2\times {{10}^{12}}$dynes

3) $2\times {{10}^{12}}$newtons

4) $2\times {{10}^{8}}$dynes

Solution:

Explanation: No Explanation

Young’s Modulus Breaking Stress

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